No, \(\frac{1}{10}\) < \(\frac{2}{11}\)
To compare these fractions, we need a common denominator. The denominators are 10 and 11, and the least common denominator (LCD) is 110.
A quicker way to compare fractions is to cross-multiply. Multiply each numerator by the other fraction's denominator:
Convert each fraction to a decimal by dividing the numerator by the denominator:
Since 0.1 is less than 0.181818, we confirm that \(\frac{1}{10} < \frac{2}{11}\). In percentage terms, \(\frac{1}{10}\) is 10% and \(\frac{2}{11}\) is 18.1818%, a difference of 8.1818 percentage points.
These fractions have different numerators and different denominators, so we can't compare them directly. By converting to a common denominator of 110, we're cutting both quantities into equal-sized pieces. Then 11 pieces vs 20 pieces is a straightforward comparison.
\(\frac{2}{11}\) is bigger. As a decimal, \(\frac{2}{11}\) = 0.181818 while \(\frac{1}{10}\) = 0.1.
The difference is \(\frac{9}{110}\), which equals 0.081818 in decimal form (8.1818 percentage points).
You can use three methods: find a common denominator and compare numerators, cross-multiply and compare the products, or convert both fractions to decimals. All three methods confirm that \(\frac{2}{11}\) \(>\) \(\frac{1}{10}\).