No, \(\frac{1}{9}\) < \(\frac{2}{11}\)
To compare these fractions, we need a common denominator. The denominators are 9 and 11, and the least common denominator (LCD) is 99.
A quicker way to compare fractions is to cross-multiply. Multiply each numerator by the other fraction's denominator:
Convert each fraction to a decimal by dividing the numerator by the denominator:
Since 0.111111 is less than 0.181818, we confirm that \(\frac{1}{9} < \frac{2}{11}\). In percentage terms, \(\frac{1}{9}\) is 11.1111% and \(\frac{2}{11}\) is 18.1818%, a difference of 7.0707 percentage points.
These fractions have different numerators and different denominators, so we can't compare them directly. By converting to a common denominator of 99, we're cutting both quantities into equal-sized pieces. Then 11 pieces vs 18 pieces is a straightforward comparison.
\(\frac{2}{11}\) is bigger. As a decimal, \(\frac{2}{11}\) = 0.181818 while \(\frac{1}{9}\) = 0.111111.
The difference is \(\frac{7}{99}\), which equals 0.070707 in decimal form (7.0707 percentage points).
You can use three methods: find a common denominator and compare numerators, cross-multiply and compare the products, or convert both fractions to decimals. All three methods confirm that \(\frac{2}{11}\) \(>\) \(\frac{1}{9}\).